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9x^2+16x^2=100
We move all terms to the left:
9x^2+16x^2-(100)=0
We add all the numbers together, and all the variables
25x^2-100=0
a = 25; b = 0; c = -100;
Δ = b2-4ac
Δ = 02-4·25·(-100)
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{10000}=100$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-100}{2*25}=\frac{-100}{50} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+100}{2*25}=\frac{100}{50} =2 $
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